Identify the structure of M based on the foll | vedclass

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(A) $1$. Compound $M$ reacts with ammoniacal $AgNO_3$ to give a white precipitate, which indicates that $M$ is a terminal alkyne $(R-C \equiv CH)$.$2$

Vedclass · Accepted Answer

$Ph-C \equiv CH$

Vedclass · Answer

(A) $1$. Compound $M$ reacts with ammoniacal $AgNO_3$ to give a white precipitate, which indicates that $M$ is a terminal alkyne $(R-C \equiv CH)$.$2$. $M$ undergoes hydrogenation with $H_2$ and Lindlar catalyst to form $N$, which is an alkene.$3$. $N$ undergoes ozonolysis to give $O$ and $P$. $O$ (benzaldehyde, $Ph-CHO$) reacts with $(CH_3CO)_2O$ and $CH_3COONa$ (Perkin's condensation) to form cinnamic acid $(Ph-CH=CH-COOH)$.$4$. Based on the reaction sequence, $M$ must be phenylacetylene $(Ph-C \equiv CH)$.$5$. $Ph-C \equiv CH + H_2 \xrightarrow{Lindlar} Ph-CH=CH_2$ $(N)$.$6$. $Ph-CH=CH_2 \xrightarrow{O_3} Ph-CHO$ $(O)$ + $HCHO$ $(P)$.$7$. Thus, $M$ is $Ph-C \equiv CH$.

Identify the structure of $M$ based on the following reaction scheme:

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