If A + B + C = frac{pi}{2},then the value of | vedclass

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(C) Given that $A + B + C = \frac{\pi}{2}$.This implies $A + B = \frac{\pi}{2} - C$.Taking the tangent on both sides,we get $	an(A + B) = 	an(\frac{

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(C) Given that $A + B + C = \frac{\pi}{2}$.This implies $A + B = \frac{\pi}{2} - C$.Taking the tangent on both sides,we get $	an(A + B) = 	an(\frac{\pi}{2} - C)$.Using the identity $	an(A + B) = \frac{	an A + 	an B}{1 - 	an A 	an B}$ and $	an(\frac{\pi}{2} - C) = \cot C = \frac{1}{	an C}$,we have:$\frac{	an A + 	an B}{1 - 	an A 	an B} = \frac{1}{	an C}$.Cross-multiplying gives:$	an C(	an A + 	an B) = 1 - 	an A 	an B$.Expanding the left side:$	an C 	an A + 	an B 	an C = 1 - 	an A 	an B$.Rearranging the terms,we get:$	an A 	an B + 	an B 	an C + 	an C 	an A = 1$.

If $A + B + C = \frac{\pi}{2}$,then the value of $\tan A \tan B + \tan B \tan C + \tan C \tan A$ is

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