If A and B are two vectors such that |A + B| | vedclass

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(D) Given the condition: $|A + B| = 2|A - B|$.Squaring both sides,we get: $|A + B|^2 = 4|A - B|^2$.Using the vector identity $|u \pm v|^2 = |u|^2 + |v

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Data insufficient

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(D) Given the condition: $|A + B| = 2|A - B|$.Squaring both sides,we get: $|A + B|^2 = 4|A - B|^2$.Using the vector identity $|u \pm v|^2 = |u|^2 + |v|^2 \pm 2|u||v| \cos 	heta$,we have:$A^2 + B^2 + 2AB \cos 	heta = 4(A^2 + B^2 - 2AB \cos 	heta)$.$A^2 + B^2 + 2AB \cos 	heta = 4A^2 + 4B^2 - 8AB \cos 	heta$.$10AB \cos 	heta = 3A^2 + 3B^2$.$\cos 	heta = \frac{3(A^2 + B^2)}{10AB}$.Since the value of $\cos 	heta$ depends on the magnitudes of $A$ and $B$,and they are not provided,the angle $	heta$ cannot be uniquely determined. Thus,the data is insufficient.

If $A$ and $B$ are two vectors such that $|A + B| = 2|A - B|$,the angle between vectors $A$ and $B$ is:

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