If z_1, z_2 and z_3, z_4 are 2 pairs of compl | vedclass

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(A) Consider the expression $\arg \left( \frac{z_1}{z_4} \right) + \arg \left( \frac{z_2}{z_3} \right)$.Using the property $\arg \left( \frac{a}{b} \r

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(A) Consider the expression $\arg \left( \frac{z_1}{z_4} \right) + \arg \left( \frac{z_2}{z_3} \right)$.Using the property $\arg \left( \frac{a}{b} \right) = \arg(a) - \arg(b)$,we get:$= \arg(z_1) - \arg(z_4) + \arg(z_2) - \arg(z_3)$Rearranging the terms,we have:$= (\arg(z_1) + \arg(z_2)) - (\arg(z_3) + \arg(z_4))$Given that $(z_1, z_2)$ and $(z_3, z_4)$ are pairs of complex conjugates,we have $z_2 = \bar{z}_1$ and $z_4 = \bar{z}_3$.Substituting these into the expression:$= (\arg(z_1) + \arg(\bar{z}_1)) - (\arg(z_3) + \arg(\bar{z}_3))$Since $\arg(\bar{z}) = -\arg(z)$,we have:$= (\arg(z_1) - \arg(z_1)) - (\arg(z_3) - \arg(z_3))$$= 0 - 0 = 0$.

If $z_1, z_2$ and $z_3, z_4$ are $2$ pairs of complex conjugate numbers,then $\arg \left( \frac{z_1}{z_4} \right) + \arg \left( \frac{z_2}{z_3} \right)$ equals

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