If r_1 and r_2 are the radii of the atomic nu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The radius of an atomic nucleus is given by the formula $r = r_0 A^{1/3}$,where $r_0$ is a constant and $A$ is the mass number.Given $A_1 = 64$ an

Vedclass · Accepted Answer

$4/5$

Vedclass · Answer

(D) The radius of an atomic nucleus is given by the formula $r = r_0 A^{1/3}$,where $r_0$ is a constant and $A$ is the mass number.Given $A_1 = 64$ and $A_2 = 125$.The ratio of the radii is $\frac{r_1}{r_2} = \left(\frac{A_1}{A_2}\right)^{1/3}$.Substituting the values,we get $\frac{r_1}{r_2} = \left(\frac{64}{125}\right)^{1/3}$.Since $64 = 4^3$ and $125 = 5^3$,we have $\frac{r_1}{r_2} = \frac{4}{5}$.

If $r_1$ and $r_2$ are the radii of the atomic nuclei of mass number $64$ and $125$ respectively,then the ratio $(r_1/r_2)$ is

Similar Questions

The most stable particle in the Baryon group is

The radius of ${ }_{29} Cu^{64}$ nucleus in Fermi is (given $R_{0}=1.2 \times 10^{-15} \ m$)

The composition of an $\alpha$-particle can be expressed as:

The radius of a nucleus of mass number $64$ is $4.8 \text{ fermi}$. Then the mass number of another nucleus having radius of $4 \text{ fermi}$ is $\frac{1000}{x}$,where $x$ is . . . . . . .

The nuclear forces are

Vedclass Test Series

Exam Paper Generator

Online Exam Module