If x runs are scored by A,y runs by B,and z r | vedclass

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(B) Given the ratios $x: y = 3: 2$ and $y: z = 3: 2$.To combine these,we make the value of $y$ common in both ratios.Multiply the first ratio by $3$ a

Vedclass · Accepted Answer

$162, 108, 72$

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(B) Given the ratios $x: y = 3: 2$ and $y: z = 3: 2$.To combine these,we make the value of $y$ common in both ratios.Multiply the first ratio by $3$ and the second ratio by $2$:$x: y = (3 	imes 3): (2 	imes 3) = 9: 6$$y: z = (3 	imes 2): (2 	imes 2) = 6: 4$Therefore,the combined ratio is $x: y: z = 9: 6: 4$.Let the runs scored be $9a, 6a,$ and $4a$.The total runs scored is $342$,so:$9a + 6a + 4a = 342$$19a = 342$$a = 342 / 19 = 18$Now,calculate the runs for each:$A = 9 	imes 18 = 162$$B = 6 	imes 18 = 108$$C = 4 	imes 18 = 72$Thus,the runs scored by $A, B,$ and $C$ are $162, 108,$ and $72$ respectively.

If $x$ runs are scored by $A$,$y$ runs by $B$,and $z$ runs by $C$,then $x: y = y: z = 3: 2$. If the total number of runs scored by $A$,$B$,and $C$ is $342$,the runs scored by each would be respectively:

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