If x * y = x^{2} + y^{2} - xy,then the value | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the operation $x * y = x^{2} + y^{2} - xy$.To find the value of $9 * 11$,substitute $x = 9$ and $y = 11$ into the given expression:$9 * 11 =

Vedclass · Accepted Answer

$103$

Vedclass · Answer

(B) Given the operation $x * y = x^{2} + y^{2} - xy$.To find the value of $9 * 11$,substitute $x = 9$ and $y = 11$ into the given expression:$9 * 11 = 9^{2} + 11^{2} - (9 	imes 11)$Calculate the squares and the product:$9^{2} = 81$$11^{2} = 121$$9 	imes 11 = 99$Substitute these values back into the expression:$9 * 11 = 81 + 121 - 99$Perform the addition and subtraction:$81 + 121 = 202$$202 - 99 = 103$Therefore,the value of $9 * 11$ is $103$.

If $x * y = x^{2} + y^{2} - xy$,then the value of $9 * 11$ is

Similar Questions

$138.009 + 341.981 - 146.305 = 123.6 + ?$

$7 \frac{1}{2}-\left[2 \frac{1}{4} \div\left\{1 \frac{1}{4}-x\left(1 \frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\right\}\right]=3$. Find the value of $x$.

What is the value of $5 \frac{1}{2} + 7 \frac{1}{2} + 11 \frac{1}{2}$?

If $a = \sqrt{2} + 1$ and $b = \sqrt{2} - 1,$ then the value of $\frac{1}{a + 1} + \frac{1}{b + 1}$ will be

$4 \frac{3}{4} + 2 \frac{1}{8} + 7 \frac{1}{4} + 3 \frac{7}{8} + 11 \frac{12}{13} = ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module