If sqrt{3} = 1.732,then the value of frac{9 + | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given expression: $\frac{9 + 2\sqrt{3}}{\sqrt{3}}$Divide each term in the numerator by the denominator:$= \frac{9}{\sqrt{3}} + \frac{2\sqrt{3}}{\s

Vedclass · Accepted Answer

$7.196$

Vedclass · Answer

(B) Given expression: $\frac{9 + 2\sqrt{3}}{\sqrt{3}}$Divide each term in the numerator by the denominator:$= \frac{9}{\sqrt{3}} + \frac{2\sqrt{3}}{\sqrt{3}}$$= \frac{9}{\sqrt{3}} + 2$Rationalize the first term:$= \frac{9 	imes \sqrt{3}}{\sqrt{3} 	imes \sqrt{3}} + 2 = \frac{9\sqrt{3}}{3} + 2 = 3\sqrt{3} + 2$Substitute the value of $\sqrt{3} = 1.732$:$= 3(1.732) + 2$$= 5.196 + 2$$= 7.196$

If $\sqrt{3} = 1.732$,then the value of $\frac{9 + 2\sqrt{3}}{\sqrt{3}}$ is

Similar Questions

$3 \div \left[ (8 - 5) \div \left\{ (4 - 2) \div \left( 2 + \frac{8}{13} \right) \right\} \right] = ?$

The value of $\frac{9^{2} \times 18^{4}}{3^{16}}$ is

The value of $\frac{3.157 \times 4126 \times 3.198}{63.972 \times 2835.121}$ is nearer to

What approximate value will come in the place of the question mark $(?)$ in the following expression? (You are not expected to calculate the exact value.)
$\frac{989}{34} \div \frac{65}{869} \times \frac{515}{207} = ?$

If we multiply a fraction by itself and divide the product by its reciprocal,the fraction thus obtained is $18 \frac{26}{27}$. The fraction is

Vedclass Test Series

Exam Paper Generator

Online Exam Module