3 div left[ (8 - 5) div left{ (4 - 2) div lef | vedclass

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Question

(A) Follow the order of operations ($BODMAS$/$PEMDAS$):First,solve the innermost parenthesis: $(2 + \frac{8}{13}) = \frac{26+8}{13} = \frac{34}{13}$.N

Vedclass · Accepted Answer

$\frac{13}{17}$

Vedclass · Answer

(A) Follow the order of operations ($BODMAS$/$PEMDAS$):First,solve the innermost parenthesis: $(2 + \frac{8}{13}) = \frac{26+8}{13} = \frac{34}{13}$.Next,solve the curly brackets: $(4 - 2) \div \frac{34}{13} = 2 \div \frac{34}{13} = 2 	imes \frac{13}{34} = \frac{13}{17}$.Then,solve the square brackets: $(8 - 5) \div \frac{13}{17} = 3 \div \frac{13}{17} = 3 	imes \frac{17}{13} = \frac{51}{13}$.Finally,solve the whole expression: $3 \div \frac{51}{13} = 3 	imes \frac{13}{51} = \frac{13}{17}$.

$3 \div \left[ (8 - 5) \div \left\{ (4 - 2) \div \left( 2 + \frac{8}{13} \right) \right\} \right] = ?$

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