If l, m, n are real and l ne m,then the roots | vedclass

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(B) The given quadratic equation is $(l - m)x^2 - 5(l + m)x - 2(l - m) = 0$.The discriminant $D$ of a quadratic equation $ax^2 + bx + c = 0$ is given

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Real and distinct

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(B) The given quadratic equation is $(l - m)x^2 - 5(l + m)x - 2(l - m) = 0$.The discriminant $D$ of a quadratic equation $ax^2 + bx + c = 0$ is given by $D = b^2 - 4ac$.Here,$a = (l - m)$,$b = -5(l + m)$,and $c = -2(l - m)$.Substituting these values into the formula for $D$:$D = [-5(l + m)]^2 - 4(l - m)[-2(l - m)]$$D = 25(l + m)^2 + 8(l - m)^2$.Since $l$ and $m$ are real and $l 
e m$,$(l - m)^2 > 0$. Also,$(l + m)^2 \ge 0$.Therefore,$D = 25(l + m)^2 + 8(l - m)^2 > 0$.Since the discriminant $D$ is strictly greater than zero,the roots of the equation are real and distinct.

If $l, m, n$ are real and $l \ne m$,then the roots of the equation $(l - m)x^2 - 5(l + m)x - 2(l - m) = 0$ are

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