If sin theta_1 + sin theta_2 + sin theta_3 = | vedclass

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(D) Given that $\sin 	heta_1 + \sin 	heta_2 + \sin 	heta_3 = 3$.Since the maximum value of the sine function is $1$,this equation can only hold tru

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(D) Given that $\sin 	heta_1 + \sin 	heta_2 + \sin 	heta_3 = 3$.Since the maximum value of the sine function is $1$,this equation can only hold true if each term is equal to $1$.Therefore,$\sin 	heta_1 = 1$,$\sin 	heta_2 = 1$,and $\sin 	heta_3 = 1$.This implies that $	heta_1 = 	heta_2 = 	heta_3 = \frac{\pi}{2}$.Now,substituting these values into the expression $\cos 	heta_1 + \cos 	heta_2 + \cos 	heta_3$:$\cos(\frac{\pi}{2}) + \cos(\frac{\pi}{2}) + \cos(\frac{\pi}{2}) = 0 + 0 + 0 = 0$.

If $\sin \theta_1 + \sin \theta_2 + \sin \theta_3 = 3$,then $\cos \theta_1 + \cos \theta_2 + \cos \theta_3 = $

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