If $\sin \alpha = -\frac{3}{5},$ where $\pi < \alpha < \frac{3\pi}{2},$ then $\cos \frac{\alpha}{2} = $

  • A
    $-\frac{1}{\sqrt{10}}$
  • B
    $\frac{1}{\sqrt{10}}$
  • C
    $\frac{3}{\sqrt{10}}$
  • D
    $-\frac{3}{\sqrt{10}}$

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