If x = a operatorname{cosec}^{n} theta and y | vedclass

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(B) Given equations are $x = a \operatorname{cosec}^{n} 	heta$ and $y = b \cot^{n} 	heta$.From these,we can write:$\operatorname{cosec} 	heta = \le

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$\left(\frac{x}{a}\right)^{\frac{2}{n}} - \left(\frac{y}{b}\right)^{\frac{2}{n}} = 1$

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(B) Given equations are $x = a \operatorname{cosec}^{n} 	heta$ and $y = b \cot^{n} 	heta$.From these,we can write:$\operatorname{cosec} 	heta = \left(\frac{x}{a}ight)^{1/n}$ and $\cot 	heta = \left(\frac{y}{b}ight)^{1/n}$.We know the trigonometric identity: $\operatorname{cosec}^{2} 	heta - \cot^{2} 	heta = 1$.Substituting the values of $\operatorname{cosec} 	heta$ and $\cot 	heta$ into the identity:$\left(\left(\frac{x}{a}ight)^{1/n}ight)^{2} - \left(\left(\frac{y}{b}ight)^{1/n}ight)^{2} = 1$.This simplifies to: $\left(\frac{x}{a}ight)^{2/n} - \left(\frac{y}{b}ight)^{2/n} = 1$.

If $x = a \operatorname{cosec}^{n} \theta$ and $y = b \cot^{n} \theta$,then by eliminating $\theta$,we get:

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