If theta+phi=frac{2 pi}{3} and cos theta=frac | vedclass

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(D) Given that $	heta+\phi=\frac{2 \pi}{3}$ and $\cos 	heta=\frac{\sqrt{3}}{2}.$Since $\cos 	heta = \frac{\sqrt{3}}{2},$ we know that $	heta = \fr

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(D) Given that $	heta+\phi=\frac{2 \pi}{3}$ and $\cos 	heta=\frac{\sqrt{3}}{2}.$Since $\cos 	heta = \frac{\sqrt{3}}{2},$ we know that $	heta = \frac{\pi}{6}$ (or $30^{\circ}$).Substituting the value of $	heta$ into the first equation:$\frac{\pi}{6} + \phi = \frac{2 \pi}{3}$$\phi = \frac{2 \pi}{3} - \frac{\pi}{6}$$\phi = \frac{4 \pi - \pi}{6} = \frac{3 \pi}{6} = \frac{\pi}{2}$Now,we need to find $\sin \phi$:$\sin \phi = \sin \left(\frac{\pi}{2}ight) = 1.$

If $\theta+\phi=\frac{2 \pi}{3}$ and $\cos \theta=\frac{\sqrt{3}}{2},$ what is the value of $\sin \phi ?$

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