If cos ^{2} x+cos ^{4} x=1, then tan ^{2} x+t | vedclass

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(B) Given: $\cos ^{2} x+\cos ^{4} x=1$We know that $\sin ^{2} x = 1 - \cos ^{2} x$.From the given equation,$\cos ^{4} x = 1 - \cos ^{2} x$,which impli

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$1$

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(B) Given: $\cos ^{2} x+\cos ^{4} x=1$We know that $\sin ^{2} x = 1 - \cos ^{2} x$.From the given equation,$\cos ^{4} x = 1 - \cos ^{2} x$,which implies $\cos ^{4} x = \sin ^{2} x$.Now,consider the expression $	an ^{2} x+	an ^{4} x$.$= 	an ^{2} x (1 + 	an ^{2} x)$$= 	an ^{2} x (\sec ^{2} x)$$= \frac{\sin ^{2} x}{\cos ^{2} x} \cdot \frac{1}{\cos ^{2} x}$$= \frac{\sin ^{2} x}{\cos ^{4} x}$Since $\sin ^{2} x = \cos ^{4} x$,we substitute this into the expression:$= \frac{\cos ^{4} x}{\cos ^{4} x} = 1$.

If $\cos ^{2} x+\cos ^{4} x=1,$ then $\tan ^{2} x+\tan ^{4} x=?$

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