If log _{10} 2986 = 3.4751,then log _{10} 0.0 | vedclass

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(B) We are given $\log _{10} 2986 = 3.4751$.We need to find $\log _{10} 0.02986$.$\log _{10} 0.02986 = \log _{10} \left( \frac{2986}{10^5} \right)$Usi

Vedclass · Accepted Answer

$\overline{2}.4751$

Vedclass · Answer

(B) We are given $\log _{10} 2986 = 3.4751$.We need to find $\log _{10} 0.02986$.$\log _{10} 0.02986 = \log _{10} \left( \frac{2986}{10^5} \right)$Using the property $\log \left( \frac{a}{b} \right) = \log a - \log b$,we get:$= \log _{10} 2986 - \log _{10} 10^5$$= 3.4751 - 5$$= -1.5249$In characteristic-mantissa form,$-1.5249 = -2 + 0.4751 = \overline{2}.4751$.

If $\log _{10} 2986 = 3.4751$,then $\log _{10} 0.02986 =$

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