If 2x,x+10,and 3x+2 are three consecutive ter | vedclass

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(D) Since $2x$,$x+10$,and $3x+2$ are three consecutive terms of an $A.P.$,the common difference between consecutive terms must be equal.Therefore,$(x+

Vedclass · Accepted Answer

$6$

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(D) Since $2x$,$x+10$,and $3x+2$ are three consecutive terms of an $A.P.$,the common difference between consecutive terms must be equal.Therefore,$(x+10) - 2x = (3x+2) - (x+10)$.Simplifying both sides:$-x + 10 = 2x - 8$.Rearranging the terms to solve for $x$:$10 + 8 = 2x + x$.$18 = 3x$.$x = \frac{18}{3} = 6$.Thus,the value of $x$ is $6$.

If $2x$,$x+10$,and $3x+2$ are three consecutive terms of an $A.P.$,find the value of $x$.

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