(C) Given that $\tan A = \cot B$.We know the trigonometric identity $\cot B = \tan(90^\circ - B)$.Substituting this into the equation,we get $\tan A =

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(C) Given that $\tan A = \cot B$.We know the trigonometric identity $\cot B = \tan(90^\circ - B)$.Substituting this into the equation,we get $\tan A = \tan(90^\circ - B)$.By comparing the angles,we have $A = 90^\circ - B$.Rearranging the terms,we get $A + B = 90^\circ$.

Class 10 Mathematics Introduction to Trigonometry Mix Examples - Introduction to Trigonometry

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If $\tan A = \cot B$,then $A + B = \ldots$

A
$30$
B
$60$
C
$90$
D
$180$

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Introduction to Trigonometry

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Mix Examples - Introduction to Trigonometry

Write 'True' or 'False' and justify your answer.
$\frac{\tan 47^{\circ}}{\cot 43^{\circ}}=1$

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$\tan 23^{\circ} \tan 42^{\circ} \tan 48^{\circ} \tan 67^{\circ} = \ldots \ldots \ldots \ldots .$

Difficult

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$\frac{\sec \theta-1}{\sec \theta+1} = \ldots$

Easy

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If $\cot \theta = \frac{a}{b}$,then $\frac{\cos \theta - \sin \theta}{\cos \theta + \sin \theta} = \ldots$

Medium

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The value of the expression $\left[\operatorname{cosec}(75^{\circ}+\theta)-\sec(15^{\circ}-\theta)-\tan(55^{\circ}+\theta)+\cot(35^{\circ}-\theta)\right]$ is

Medium

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If $\tan A = \cot B$,then $A + B = \ldots$

Similar Questions

Write 'True' or 'False' and justify your answer.$\frac{\tan 47^{\circ}}{\cot 43^{\circ}}=1$

$\tan 23^{\circ} \tan 42^{\circ} \tan 48^{\circ} \tan 67^{\circ} = \ldots \ldots \ldots \ldots .$

$\frac{\sec \theta-1}{\sec \theta+1} = \ldots$

If $\cot \theta = \frac{a}{b}$,then $\frac{\cos \theta - \sin \theta}{\cos \theta + \sin \theta} = \ldots$

The value of the expression $\left[\operatorname{cosec}(75^{\circ}+\theta)-\sec(15^{\circ}-\theta)-\tan(55^{\circ}+\theta)+\cot(35^{\circ}-\theta)\right]$ is

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Write 'True' or 'False' and justify your answer.
$\frac{\tan 47^{\circ}}{\cot 43^{\circ}}=1$