If 5 theta is the measure of an acute angle a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given equation: $\cos 	heta = \sin 5 	heta$We know that $\sin(90^{\circ} - A) = \cos A$,so $\sin 5 	heta = \cos(90^{\circ} - 5 	heta)$.Substit

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(C) Given equation: $\cos 	heta = \sin 5 	heta$We know that $\sin(90^{\circ} - A) = \cos A$,so $\sin 5 	heta = \cos(90^{\circ} - 5 	heta)$.Substituting this into the equation: $\cos 	heta = \cos(90^{\circ} - 5 	heta)$.Since the cosine function is one-to-one for acute angles,we can equate the arguments:$	heta = 90^{\circ} - 5 	heta$$	heta + 5 	heta = 90^{\circ}$$6 	heta = 90^{\circ}$$	heta = \frac{90^{\circ}}{6} = 15^{\circ}$.

If $5 \theta$ is the measure of an acute angle and $\cos \theta = \sin 5 \theta$,then the value of $\theta$ is $\ldots \ldots \ldots \ldots$ (in $^{\circ}$)

Similar Questions

If $\cos \theta = \frac{1}{\sqrt{2}},$ then $\theta = \ldots$ (in $^\circ$)

Write 'True' or 'False' and justify your answer.
$\frac{\tan 47^{\circ}}{\cot 43^{\circ}}=1$

Prove that,
$(\sqrt{3}+ 1) (3-\cot 30^{\circ})=\tan ^{3} 60^{\circ}-2 \sin 60^{\circ}$

If $\sec ^{2} \theta+\tan ^{2} \theta=\frac{13}{12}$,then the value of $\sec ^{4} \theta-\tan ^{4} \theta$ is .........

If $\tan \theta = 1$,then $\sin \theta \cdot \cos \theta = \dots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module