If Z = 36.8 and M = 33.6,then bar{x} = ldots | vedclass

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(C) The empirical relationship between Mean $(\bar{x})$,Median $(M)$,and Mode $(Z)$ is given by the formula:$Z = 3M - 2\bar{x}$Given values are $Z = 3

Vedclass · Accepted Answer

$32$

Vedclass · Answer

(C) The empirical relationship between Mean $(\bar{x})$,Median $(M)$,and Mode $(Z)$ is given by the formula:$Z = 3M - 2\bar{x}$Given values are $Z = 36.8$ and $M = 33.6$.Substituting these values into the formula:$36.8 = 3(33.6) - 2\bar{x}$Calculate $3 	imes 33.6$:$36.8 = 100.8 - 2\bar{x}$Rearrange the equation to solve for $\bar{x}$:$2\bar{x} = 100.8 - 36.8$$2\bar{x} = 64$Divide by $2$:$\bar{x} = \frac{64}{2} = 32$Thus,the value of $\bar{x}$ is $32$.

Weight (in $g$)	Number of packets
$200-201$	$12$
$201-202$	$26$
$202-203$	$20$
$203-204$	$9$
$204-205$	$2$
$205-206$	$1$

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$
Frequency	$6$	$f_1$	$20$	$15$	$f_2$	$4$

If $Z = 36.8$ and $M = 33.6$,then $\bar{x} = \ldots \ldots \ldots \ldots .$

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