If x = 10.0 pm 0.1 and y = 10.0 pm 0.1,then 2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given $x = 10.0 \pm 0.1$ and $y = 10.0 \pm 0.1$.We need to find the value of $z = 2x - 2y$.First,calculate the mean value: $z = 2(10.0) - 2(10.0)

Vedclass · Accepted Answer

$(0.0 \pm 0.4)$

Vedclass · Answer

(A) Given $x = 10.0 \pm 0.1$ and $y = 10.0 \pm 0.1$.We need to find the value of $z = 2x - 2y$.First,calculate the mean value: $z = 2(10.0) - 2(10.0) = 20.0 - 20.0 = 0.0$.Next,calculate the absolute error in $z$. For an expression $z = ax - by$,the absolute error $\Delta z$ is given by $\Delta z = |a|\Delta x + |b|\Delta y$.Here,$a = 2$ and $b = 2$,so $\Delta z = 2(0.1) + 2(0.1) = 0.2 + 0.2 = 0.4$.Thus,$2x - 2y = 0.0 \pm 0.4$.

If $x = 10.0 \pm 0.1$ and $y = 10.0 \pm 0.1$,then $2x - 2y$ is equal to

Similar Questions

In Ohm's experiment,the values of an unknown resistance were found to be $4.12 \; \Omega, 4.08 \; \Omega, 4.22 \; \Omega$,and $4.14 \; \Omega$. Calculate the mean absolute error and relative error in these measurements.

The error in the measurement of the radius of a sphere is $1\%$. The error in the calculated value of its volume is ......... $\%$

Error in the measurement of radius of a sphere is $0.2\%$. The error in the calculated value of its volume is ......... $\%$

Write the rule for the error produced in the result due to the addition and subtraction of physical quantities.

Out of absolute error,relative error,and fractional error,which has a unit and which has no unit?

Vedclass Test Series

Exam Paper Generator

Online Exam Module