If A is the set of even natural numbers less | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Step $1$: Identify the elements of set $A$. The even natural numbers less than $8$ are $2, 4, 6$. So,$A = \{2, 4, 6\}$.Step $2$: Identify the elem

Vedclass · Accepted Answer

$2^9$

Vedclass · Answer

(A) Step $1$: Identify the elements of set $A$. The even natural numbers less than $8$ are $2, 4, 6$. So,$A = \{2, 4, 6\}$.Step $2$: Identify the elements of set $B$. The prime numbers less than $7$ are $2, 3, 5$. So,$B = \{2, 3, 5\}$.Step $3$: Calculate the number of elements in the Cartesian product $A 	imes B$. The number of elements $n(A) = 3$ and $n(B) = 3$. Thus,$n(A 	imes B) = n(A) 	imes n(B) = 3 	imes 3 = 9$.Step $4$: The number of relations from $A$ to $B$ is the number of subsets of $A 	imes B$,which is given by $2^{n(A 	imes B)} = 2^9$.

If $A$ is the set of even natural numbers less than $8$ and $B$ is the set of prime numbers less than $7$,then the number of relations from $A$ to $B$ is

Similar Questions

Let $R$ be a relation in the set of natural numbers $N$ defined by $R = \{(a, b) : a = b - 2, b > 6\}$. Which of the following is correct?

Let $A = \{1, 2, 3, 4\}$,$B = \{1, 5, 9, 11, 15, 16\}$,and $f = \{(1, 5), (2, 9), (3, 1), (4, 5), (2, 11)\}$. Is $f$ a relation from $A$ to $B$? Justify your answer.

Write the relation $R = \{ (x, x^3) : x \text{ is a prime number less than } 10 \}$ in roster form.

If $R=\{(x, y): x, y \in Z, x^{2}+3 y^{2} \leq 8\}$ is a relation on the set of integers $Z,$ then the domain of $R^{-1}$ is

If $R = \{(a, b) : b = a - 1, a \in \mathbb{Z}, 5 < a < 9\}$,then the range of $R$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module