If x = log_{b}a,y = log_{c}b,and z = log_{a}c | vedclass

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(B) Given that $x = \log_{b}a$,$y = \log_{c}b$,and $z = \log_{a}c$.We need to find the product $xyz$.Using the change of base formula,$\log_{n}m = \fr

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$1$

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(B) Given that $x = \log_{b}a$,$y = \log_{c}b$,and $z = \log_{a}c$.We need to find the product $xyz$.Using the change of base formula,$\log_{n}m = \frac{\log_{k}m}{\log_{k}n}$,we can write:$x = \frac{\log a}{\log b}$,$y = \frac{\log b}{\log c}$,and $z = \frac{\log c}{\log a}$.Now,multiply these values:$xyz = \left(\frac{\log a}{\log b}ight) 	imes \left(\frac{\log b}{\log c}ight) 	imes \left(\frac{\log c}{\log a}ight)$.Canceling the common terms in the numerator and denominator,we get:$xyz = 1$.

If $x = \log_{b}a$,$y = \log_{c}b$,and $z = \log_{a}c$,then the value of $xyz$ is

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