If $\frac{2x}{x^3 - 1} = \frac{A}{x - 1} + \frac{Bx + C}{x^2 + x + 1}$,then

  • A
    $A = B = C$
  • B
    $A = B \neq C$
  • C
    $A \neq B = C$
  • D
    $A \neq B \neq C$

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