If x = log_{3} 5 and y = log_{17} 25,which on | vedclass

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(C) Given $x = \log_{3} 5$ and $y = \log_{17} 25 = 2 \log_{17} 5$.Taking the reciprocal of $y$,we get $\frac{1}{y} = \frac{1}{2 \log_{17} 5} = \frac{1

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$x > y$

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(C) Given $x = \log_{3} 5$ and $y = \log_{17} 25 = 2 \log_{17} 5$.Taking the reciprocal of $y$,we get $\frac{1}{y} = \frac{1}{2 \log_{17} 5} = \frac{1}{2} \log_{5} 17 = \log_{5} (17^{1/2}) = \log_{5} \sqrt{17}$.Taking the reciprocal of $x$,we get $\frac{1}{x} = \log_{5} 3 = \log_{5} \sqrt{9}$.Since $\sqrt{17} > \sqrt{9}$,it follows that $\log_{5} \sqrt{17} > \log_{5} \sqrt{9}$.Therefore,$\frac{1}{y} > \frac{1}{x}$,which implies $x > y$.

If $x = \log_{3} 5$ and $y = \log_{17} 25$,which one of the following is correct?

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