If bar{x} is a non-zero vector and k 0, k n | vedclass

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Question

(C) Let $\bar{u} = \frac{\bar{x}}{|\bar{x}|}$ be the unit vector in the direction of $\bar{x}$.Then the given expression is $-k \bar{u}$.Since $k > 0$

Vedclass · Accepted Answer

in the opposite direction of $\bar{x}$ having magnitude $k$

Vedclass · Answer

(C) Let $\bar{u} = \frac{\bar{x}}{|\bar{x}|}$ be the unit vector in the direction of $\bar{x}$.Then the given expression is $-k \bar{u}$.Since $k > 0$,the magnitude of $-k \bar{u}$ is $|-k| |\bar{u}| = k 	imes 1 = k$.The negative sign indicates that the vector is in the opposite direction of $\bar{u}$,which is the opposite direction of $\bar{x}$.Therefore,the vector is in the opposite direction of $\bar{x}$ and has a magnitude of $k$.

If $\bar{x}$ is a non-zero vector and $k > 0, k \neq 1$,then $\frac{-k \bar{x}}{|\bar{x}|}$ is $.......$ .

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