If a, b, c are positive integers,then (a + b) | vedclass

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(B) Since $A.M. > G.M.$ for positive real numbers,we have:$\frac{a + b}{2} > \sqrt{ab}$$\frac{b + c}{2} > \sqrt{bc}$$\frac{c + a}{2} > \sqrt{ca}$Multi

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$> 8abc$

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(B) Since $A.M. > G.M.$ for positive real numbers,we have:$\frac{a + b}{2} > \sqrt{ab}$$\frac{b + c}{2} > \sqrt{bc}$$\frac{c + a}{2} > \sqrt{ca}$Multiplying these three inequalities,we get:$\frac{(a + b)(b + c)(c + a)}{8} > \sqrt{ab \cdot bc \cdot ca}$$\frac{(a + b)(b + c)(c + a)}{8} > \sqrt{a^2 b^2 c^2}$$\frac{(a + b)(b + c)(c + a)}{8} > abc$$(a + b)(b + c)(c + a) > 8abc$.

If $a, b, c$ are positive integers,then $(a + b)(b + c)(c + a)$ is

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