જો $y = 1 + x + \frac{x^{2}}{2!} + \frac{x^{3}}{3!} + \dots$ હોય,તો $\frac{dy}{dx} = $

  • A
    $y - 1$
  • B
    $y + 1$
  • C
    $y^{2} - 1$
  • D
    $y$

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Similar Questions

જો $x \neq 0$ અને $f(x)$ એ $8 f(x) + 6 f(\frac{1}{x}) = x + 5$ નું પાલન કરે છે,તો $x = 1$ આગળ $\frac{d}{dx} (x^2 f(x))$ ની કિંમત શોધો.

જો $y=1+x+\frac{x^2}{2!}+\frac{x^3}{3!}+\ldots$ હોય,તો $\frac{dy}{dx}=$ . . . . . . .

$g(x) = \cot x$ નું વિકલન શોધો.

જો $f(x) = \sqrt{x + 2 \sqrt{2x - 4}} + \sqrt{x - 2 \sqrt{2x - 4}}$ હોય,તો $10 \times f^{\prime}(102)$ ની કિંમત શોધો.

જો $y(\alpha)=\sqrt{2\left(\frac{\tan \alpha+\cot \alpha}{1+\tan ^{2} \alpha}\right)+\frac{1}{\sin ^{2} \alpha}}$ જ્યાં $\alpha \in\left(\frac{3 \pi}{4}, \pi\right)$ હોય,તો $\alpha=\frac{5 \pi}{6}$ આગળ $\frac{d y}{d \alpha}$ શોધો.

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