If $\int \frac{\sqrt{x}}{x(x+1)} dx = k \tan^{-1} m + c$,(where $c$ is the constant of integration),then:
- A$k=1, m=\sqrt{x}$
- B$k=2, m=\sqrt{x}$
- C$k=1, m=x$
- D$k=2, m=x$
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