If A = begin{bmatrix} cos theta & -sin theta | vedclass

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(C) Given $A = \begin{bmatrix} \cos 	heta & -\sin 	heta & 0 \ \sin 	heta & \cos 	heta & 0 \ 0 & 0 & 1 \end{bmatrix}$.The adjoint of a matrix $A$

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$\begin{bmatrix} \cos 	heta & \sin 	heta & 0 \ -\sin 	heta & \cos 	heta & 0 \ 0 & 0 & 1 \end{bmatrix}$

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(C) Given $A = \begin{bmatrix} \cos 	heta & -\sin 	heta & 0 \ \sin 	heta & \cos 	heta & 0 \ 0 & 0 & 1 \end{bmatrix}$.The adjoint of a matrix $A$,denoted by $\operatorname{adj} A$,is the transpose of the cofactor matrix $C = [C_{ij}]$.Calculating the cofactors: $C_{11} = (\cos 	heta)(1) - 0 = \cos 	heta$,$C_{12} = -(\sin 	heta(1) - 0) = -\sin 	heta$,$C_{13} = 0$.$C_{21} = -(-\sin 	heta(1) - 0) = \sin 	heta$,$C_{22} = (\cos 	heta)(1) - 0 = \cos 	heta$,$C_{23} = 0$.$C_{31} = 0$,$C_{32} = 0$,$C_{33} = \cos^2 	heta + \sin^2 	heta = 1$.Thus,the cofactor matrix is $\begin{bmatrix} \cos 	heta & -\sin 	heta & 0 \ \sin 	heta & \cos 	heta & 0 \ 0 & 0 & 1 \end{bmatrix}$.Taking the transpose,$\operatorname{adj} A = \begin{bmatrix} \cos 	heta & \sin 	heta & 0 \ -\sin 	heta & \cos 	heta & 0 \ 0 & 0 & 1 \end{bmatrix}$.

If $A = \begin{bmatrix} \cos \theta & -\sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1 \end{bmatrix}$,then $\operatorname{adj} A = $

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