If p is a prime number,then n^p - n is divisi | vedclass

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(A) According to Fermat's Little Theorem,if $p$ is a prime number,then for any integer $n$,$n^p \equiv n \pmod{p}$.This implies that $n^p - n$ is divi

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Natural number

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(A) According to Fermat's Little Theorem,if $p$ is a prime number,then for any integer $n$,$n^p \equiv n \pmod{p}$.This implies that $n^p - n$ is divisible by $p$ for any integer $n$.Since the options provided focus on the set of natural numbers,the statement holds true for any natural number $n \geq 1$.For example,let $n = 2$ and $p = 3$:$2^3 - 2 = 8 - 2 = 6$,which is divisible by $3$.

If $p$ is a prime number,then $n^p - n$ is divisible by $p$ when $n$ is a

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