If $A = \begin{bmatrix} 2 & -2 \\ 4 & 3 \end{bmatrix}$,then $A^{-1} =$
- A$-\frac{1}{2} \begin{bmatrix} 3 & 2 \\ -4 & 2 \end{bmatrix}$
- B$\frac{1}{14} \begin{bmatrix} 3 & 2 \\ -4 & 2 \end{bmatrix}$
- C$\frac{1}{14} \begin{bmatrix} -3 & -2 \\ 4 & -2 \end{bmatrix}$
- D$-\frac{1}{14} \begin{bmatrix} 3 & -2 \\ 4 & -2 \end{bmatrix}$
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DifficultMHT CET 2026
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