If $A$ and $B$ are independent events such that odds in favour of $A$ is $2:3$ and odds against $B$ is $4:5$,then $P(A \cap B)=$

  • A
    $\frac{1}{9}$
  • B
    $\frac{4}{5}$
  • C
    $\frac{2}{9}$
  • D
    $\frac{3}{9}$

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