If (bar{a} times bar{b}) times bar{c} = -5 ba | vedclass

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Question

(C) We know the vector triple product formula: $(\bar{a} 	imes \bar{b}) 	imes \bar{c} = (\bar{a} \cdot \bar{c}) \bar{b} - (\bar{b} \cdot \bar{c}) \b

Vedclass · Accepted Answer

$4 \bar{b} - 3 \bar{c}$

Vedclass · Answer

(C) We know the vector triple product formula: $(\bar{a} 	imes \bar{b}) 	imes \bar{c} = (\bar{a} \cdot \bar{c}) \bar{b} - (\bar{b} \cdot \bar{c}) \bar{a}$.Given that $(\bar{a} 	imes \bar{b}) 	imes \bar{c} = -5 \bar{a} + 4 \bar{b}$.Comparing the coefficients of $\bar{a}$ and $\bar{b}$,we get:$-(\bar{b} \cdot \bar{c}) = -5 \implies \bar{b} \cdot \bar{c} = 5$$(\bar{a} \cdot \bar{c}) = 4$Now,we need to find $\bar{a} 	imes (\bar{b} 	imes \bar{c})$.Using the vector triple product formula: $\bar{a} 	imes (\bar{b} 	imes \bar{c}) = (\bar{a} \cdot \bar{c}) \bar{b} - (\bar{a} \cdot \bar{b}) \bar{c}$.Substituting the known values $\bar{a} \cdot \bar{c} = 4$ and $\bar{a} \cdot \bar{b} = 3$:$\bar{a} 	imes (\bar{b} 	imes \bar{c}) = 4 \bar{b} - 3 \bar{c}$.

If $(\bar{a} \times \bar{b}) \times \bar{c} = -5 \bar{a} + 4 \bar{b}$ and $\bar{a} \cdot \bar{b} = 3$,then the value of $\bar{a} \times (\bar{b} \times \bar{c})$ is

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