If A and B are square matrices of order 2,the | vedclass

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(B) For any two square matrices $A$ and $B$ of the same order,the square of their sum is defined as:$(A + B)^2 = (A + B)(A + B)$Expanding the product

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$A^2 + AB + BA + B^2$

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(B) For any two square matrices $A$ and $B$ of the same order,the square of their sum is defined as:$(A + B)^2 = (A + B)(A + B)$Expanding the product using the distributive property of matrix multiplication:$(A + B)(A + B) = A(A + B) + B(A + B)$$= A^2 + AB + BA + B^2$Since matrix multiplication is generally not commutative (i.e.,$AB 
eq BA$ in general),we cannot simplify $AB + BA$ to $2AB$. Therefore,the correct expression is $A^2 + AB + BA + B^2$.

If $A$ and $B$ are square matrices of order $2$,then $(A + B)^2 = $

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