If A = begin{bmatrix} i & 0 0 & i end{bmatri | vedclass

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(B) Given $A = \begin{bmatrix} i & 0 \ 0 & i \end{bmatrix}$.To find ${A^2}$,we calculate $A 	imes A$:${A^2} = \begin{bmatrix} i & 0 \ 0 & i \end{bm

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$\begin{bmatrix} -1 & 0 \ 0 & -1 \end{bmatrix}$

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(B) Given $A = \begin{bmatrix} i & 0 \ 0 & i \end{bmatrix}$.To find ${A^2}$,we calculate $A 	imes A$:${A^2} = \begin{bmatrix} i & 0 \ 0 & i \end{bmatrix} \begin{bmatrix} i & 0 \ 0 & i \end{bmatrix}$Performing matrix multiplication:${A^2} = \begin{bmatrix} (i 	imes i) + (0 	imes 0) & (i 	imes 0) + (0 	imes i) \ (0 	imes i) + (i 	imes 0) & (0 	imes 0) + (i 	imes i) \end{bmatrix}$${A^2} = \begin{bmatrix} i^2 & 0 \ 0 & i^2 \end{bmatrix}$Since $i^2 = -1$,we substitute this value:${A^2} = \begin{bmatrix} -1 & 0 \ 0 & -1 \end{bmatrix}$.

If $A = \begin{bmatrix} i & 0 \\ 0 & i \end{bmatrix}$,then ${A^2} = $

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