If $M_0$ and $L_0$ denote the magnetic moment and angular momentum of the electron due to its orbital motion respectively,then the gyromagnetic ratio is given by

The angle made by the orbital angular momentum of an electron with the direction of its orbital magnetic moment is: (in $^{\circ}$)

$A$ model for quantized motion of an electron in a uniform magnetic field $B$ states that the flux passing through the orbit of the electron is $n(h / e)$ where $n$ is an integer,$h$ is Planck's constant and $e$ is the magnitude of electron's charge. According to the model,the magnetic moment of an electron in its lowest energy state will be ($m$ is the mass of the electron).

If the charge to mass ratio of an electron is $A \ C/kg$,then the gyromagnetic ratio of an orbital electron in $C/kg$ is

$A$ particle of charge '$q$' and mass '$m$' moves in a circular orbit of radius '$r$' with angular speed '$\omega$'. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

If the angular momentum of an electron is $\vec{J}$,then the magnitude of the magnetic moment will be: