જો $5 \tan \theta = 4$ હોય,તો $\frac{5 \sin \theta - 3 \cos \theta}{5 \sin \theta + 2 \cos \theta} = $

  • A
    $0$
  • B
    $1$
  • C
    $1/6$
  • D
    $6$

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Similar Questions

સાબિત કરો કે $\cos \left(\frac{3 \pi}{2}+x\right) \cos (2 \pi+x)\left[\cot \left(\frac{3 \pi}{2}-x\right)+\cot (2 \pi+x)\right]=1$.

$\tan \theta \sin \left( \frac{\pi }{2} + \theta \right) \cos \left( \frac{\pi }{2} - \theta \right) = $

નીચેનામાંથી કયો સંબંધ શક્ય છે?

જો $\sec \theta = \frac{13}{12}$ અને $\theta$ એ $4^{\text{th}}$ ચરણમાં હોય,તો $\tan \theta \times \operatorname{cosec} \theta \times \sin \theta \times \cos \theta = $

પદાવલિ $\tan(x - 9\pi)$ ની કિંમત કોના બરાબર છે:

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