(A) Since $(x-1)$ is a factor of $x^{5}-4 x^{3}+2 x^{2}-3 x+k=0$,by the factor theorem,$x=1$ must satisfy the given equation.Substituting $x=1$ into t

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(A) Since $(x-1)$ is a factor of $x^{5}-4 x^{3}+2 x^{2}-3 x+k=0$,by the factor theorem,$x=1$ must satisfy the given equation.Substituting $x=1$ into the equation:$(1)^{5}-4(1)^{3}+2(1)^{2}-3(1)+k=0$$1-4+2-3+k=0$$-4+k=0$$k=4$

Class 11 Mathematics 4-2.Quadratic Equations and Inequations Solution of quadratic equations and Nature of roots

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If $(x-1)$ is a factor of the polynomial $x^{5}-4 x^{3}+2 x^{2}-3 x+k=0$,then the value of $k$ is:

KCET 2012 All KCET

A
$4$
B
$-4$
C
$2$
D
$3$

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4-2.Quadratic Equations and Inequations

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Solution of quadratic equations and Nature of roots

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