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(A) Given $	an m	heta = 	an n	heta$.Using the general solution for $	an x = 	an y$,we have $m	heta = p\pi + n	heta$,where $p \in \mathbb{Z}$.R

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(A) Given $	an m	heta = 	an n	heta$.Using the general solution for $	an x = 	an y$,we have $m	heta = p\pi + n	heta$,where $p \in \mathbb{Z}$.Rearranging the terms,we get $(m - n)	heta = p\pi$.Thus,$	heta = \frac{p\pi}{m - n}$.For different integer values of $p$ $(p = 0, 1, 2, \dots)$,the values of $	heta$ are $0, \frac{\pi}{m - n}, \frac{2\pi}{m - n}, \dots$.These values form an arithmetic progression $(A.P.)$ with a common difference of $\frac{\pi}{m - n}$.

If $\tan m\theta = \tan n\theta$,then the general values of $\theta$ are in

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