If sin^{-1} x + cos^{-1} y = frac{2pi}{5},the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given that,$\sin^{-1} x + \cos^{-1} y = \frac{2\pi}{5} \quad (1)$We know the fundamental identities: $\sin^{-1} x + \cos^{-1} x = \frac{\pi}{2}$ a

Vedclass · Accepted Answer

$\frac{3\pi}{5}$

Vedclass · Answer

(B) Given that,$\sin^{-1} x + \cos^{-1} y = \frac{2\pi}{5} \quad (1)$We know the fundamental identities: $\sin^{-1} x + \cos^{-1} x = \frac{\pi}{2}$ and $\sin^{-1} y + \cos^{-1} y = \frac{\pi}{2}$.From these,we can write $\sin^{-1} x = \frac{\pi}{2} - \cos^{-1} x$ and $\cos^{-1} y = \frac{\pi}{2} - \sin^{-1} y$.Substituting these into equation $(1)$:$(\frac{\pi}{2} - \cos^{-1} x) + (\frac{\pi}{2} - \sin^{-1} y) = \frac{2\pi}{5}$$\pi - (\cos^{-1} x + \sin^{-1} y) = \frac{2\pi}{5}$$\cos^{-1} x + \sin^{-1} y = \pi - \frac{2\pi}{5}$$\cos^{-1} x + \sin^{-1} y = \frac{3\pi}{5}$

If $\sin^{-1} x + \cos^{-1} y = \frac{2\pi}{5}$,then $\cos^{-1} x + \sin^{-1} y$ is

Similar Questions

Prove that $\sin ^{-1} \frac{8}{17}+\sin ^{-1} \frac{3}{5}=\tan ^{-1} \frac{77}{36}$

$\sin \left\{ {{\sin }^{ - 1}}\frac{1}{2} + {{\cos }^{ - 1}}\frac{1}{2} \right\} = $

The value of the expression $ \tan \left(\frac{1}{2} \cos ^{-1} \frac{2}{\sqrt{5}}\right) $ is

If $ a + \frac{\pi}{2} < 2 \tan^{-1} x + 3 \cot^{-1} x < b $,then find the values of $ a $ and $ b $.

The trigonometric equation $\sin ^{-1} x = 2 \sin ^{-1} 2a$ has a real solution, if

Vedclass Test Series

Exam Paper Generator

Online Exam Module