If a and b are the order and degree respectiv | vedclass

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(D) The given differential equation is $\left(\frac{d^2 y}{d x^2}\right)^2+\left(\frac{d y}{d x}\right)^3+x^4=0$. The order of a differential equation

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(D) The given differential equation is $\left(\frac{d^2 y}{d x^2}\right)^2+\left(\frac{d y}{d x}\right)^3+x^4=0$. The order of a differential equation is the order of the highest derivative present in the equation. Here,the highest derivative is $\frac{d^2 y}{d x^2}$,so the order $a = 2$. The degree of a differential equation is the power of the highest derivative when the equation is expressed as a polynomial in derivatives. Here,the power of the highest derivative $\frac{d^2 y}{d x^2}$ is $2$,so the degree $b = 2$. Therefore,$a - b = 2 - 2 = 0$.

If $a$ and $b$ are the order and degree respectively of the differential equation $\left(\frac{d^2 y}{d x^2}\right)^2+\left(\frac{d y}{d x}\right)^3+x^4=0$,then $a-b=$

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