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Question

(A) The order of a differential equation is defined as the order of the highest derivative present in the equation. In the given differential equation

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) The order of a differential equation is defined as the order of the highest derivative present in the equation. In the given differential equation $\left(\frac{d^3 y}{d x^3}\right)^4+\left(\frac{d^2 y}{d x^2}\right)^2+\sin \left(\frac{d y}{d x}\right)+1=0$,the derivatives present are $\frac{d^3 y}{d x^3}$,$\frac{d^2 y}{d x^2}$,and $\frac{d y}{d x}$. The highest order derivative is $\frac{d^3 y}{d x^3}$,which is of order $3$. Therefore,the order of the differential equation is $3$.

The order of the differential equation $\left(\frac{d^3 y}{d x^3}\right)^4+\left(\frac{d^2 y}{d x^2}\right)^2+\sin \left(\frac{d y}{d x}\right)+1=0$ is . . . . . . .

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