If $a=(1,2,3), b=(2,-1,1), c=(3,2,1)$ and $a \times(b \times c)=\alpha a+\beta b+\gamma c$,then

  • A
    $\alpha=1, \beta=10, \gamma=3$
  • B
    $\alpha=0, \beta=10, \gamma=-3$
  • C
    $\alpha+\beta+\gamma=8$
  • D
    $\alpha=\beta=\gamma=0$

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