If sin^{-1} x + sin^{-1} y = frac{2pi}{3},the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) We know the identity $\sin^{-1} x + \cos^{-1} x = \frac{\pi}{2}$ for $x \in [-1, 1]$.Therefore,$\sin^{-1} x = \frac{\pi}{2} - \cos^{-1} x$ and $\s

Vedclass · Accepted Answer

$\frac{\pi}{3}$

Vedclass · Answer

(B) We know the identity $\sin^{-1} x + \cos^{-1} x = \frac{\pi}{2}$ for $x \in [-1, 1]$.Therefore,$\sin^{-1} x = \frac{\pi}{2} - \cos^{-1} x$ and $\sin^{-1} y = \frac{\pi}{2} - \cos^{-1} y$.Substituting these into the given equation:$(\frac{\pi}{2} - \cos^{-1} x) + (\frac{\pi}{2} - \cos^{-1} y) = \frac{2\pi}{3}$$\pi - (\cos^{-1} x + \cos^{-1} y) = \frac{2\pi}{3}$$\cos^{-1} x + \cos^{-1} y = \pi - \frac{2\pi}{3}$$\cos^{-1} x + \cos^{-1} y = \frac{\pi}{3}$.

If $\sin^{-1} x + \sin^{-1} y = \frac{2\pi}{3}$,then $\cos^{-1} x + \cos^{-1} y = $

Similar Questions

If $y = \cos^{-1}\left( \frac{3\cos x + 4\sin x}{5} \right)$,then $\frac{dy}{dx} = $

If $3 \tan^{-1} x + \cot^{-1} x = \pi$,then $x$ is equal to:

If $y = \cos^2 [\cot^{-1} (\sqrt{\frac{1-x}{1+x}})]$, then $\frac{dy}{dx} = \dots$

The derivative of $\cos ^{-1}\left(2 x^{2}-1\right)$ with respect to $\cos ^{-1} x$ is

If $\cot(\cos^{-1} x) = \sec(\tan^{-1} \frac{a}{\sqrt{b^2 - a^2}})$, then the value of $x$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module