(B) Given the cubic equation: $x^3+3x^2-7x+5=0$. Let $\alpha, \beta, \gamma$ be the roots of the equation. From the relationship between roots and coe

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(B) Given the cubic equation: $x^3+3x^2-7x+5=0$. Let $\alpha, \beta, \gamma$ be the roots of the equation. From the relationship between roots and coefficients: $\alpha+\beta+\gamma = -3$ $\alpha\beta+\beta\gamma+\gamma\alpha = -7$ $\alpha\beta\gamma = -5$ We need to find the value of $\frac{1}{\alpha}+\frac{1}{\beta}+\frac{1}{\gamma}$. $\frac{1}{\alpha}+\frac{1}{\beta}+\frac{1}{\gamma} = \frac{\beta\gamma+\alpha\gamma+\alpha\beta}{\alpha\beta\gamma} = \frac{-7}{-5} = \frac{7}{5}$.

Class 11 Mathematics 4-2.Quadratic Equations and Inequations Relation between roots and coefficients

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If $\alpha, \beta$ and $\gamma$ are the roots of the equation $x^3+3x^2-7x+5=0$,then the value of $\frac{1}{\alpha}+\frac{1}{\beta}+\frac{1}{\gamma}$ is

AP EAMCET 2021 All AP EAMCET

A
$\frac{-7}{5}$
B
$\frac{7}{5}$
C
$\frac{-3}{5}$
D
$\frac{3}{5}$

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4-2.Quadratic Equations and Inequations

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If $\alpha, \beta$ and $\gamma$ are the roots of the equation $x^3+3x^2-7x+5=0$,then the value of $\frac{1}{\alpha}+\frac{1}{\beta}+\frac{1}{\gamma}$ is

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