If $\alpha = \frac{180^{\circ}}{7}$,then $3 \sin \alpha - 4 \sin^{3} \alpha$ is equal to

  • A
    $\cos 4 \alpha$
  • B
    $\sin 4 \alpha$
  • C
    $\cos 3 \alpha$
  • D
    $0$

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