If A+B=frac{pi}{4},then frac{cos B-sin B}{cos | vedclass

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Question

(C) Given $A+B = \frac{\pi}{4}$,so $A = \frac{\pi}{4} - B$. Divide the numerator and denominator by $\cos B$: $\frac{\cos B - \sin B}{\cos B + \sin B}

Vedclass · Accepted Answer

$	an A$

Vedclass · Answer

(C) Given $A+B = \frac{\pi}{4}$,so $A = \frac{\pi}{4} - B$. Divide the numerator and denominator by $\cos B$: $\frac{\cos B - \sin B}{\cos B + \sin B} = \frac{1 - 	an B}{1 + 	an B}$. We know that $	an(\frac{\pi}{4} - B) = \frac{	an(\frac{\pi}{4}) - 	an B}{1 + 	an(\frac{\pi}{4})	an B}$. Since $	an(\frac{\pi}{4}) = 1$,this becomes $\frac{1 - 	an B}{1 + 	an B} = 	an(\frac{\pi}{4} - B)$. Substituting $A = \frac{\pi}{4} - B$,we get $	an A$.

If $A+B=\frac{\pi}{4}$,then $\frac{\cos B-\sin B}{\cos B+\sin B}=$

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