If $\sin A+\sin B+\sin C=0$ and $\cos A+\cos B+\cos C=0$,then $\cos (A+B)+\cos (B+C)+\cos (C+A)$ is equal to

  • A
    $\cos (A+B+C)$
  • B
    $2$
  • C
    $1$
  • D
    $0$

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