If $x$ is numerically so small that $x^2$ and higher powers of $x$ can be neglected,then $\left(1+\frac{2 x}{3}\right)^{3 / 2} \cdot(32+5 x)^{-1 / 5}$ is approximately equal to

  • A
    $\frac{32+31 x}{64}$
  • B
    $\frac{31+32 x}{64}$
  • C
    $\frac{31-32 x}{64}$
  • D
    $\frac{1-2 x}{64}$

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